First, we started by trying to obtain a sample of 160 North Olmsted High
School students, which would be about 10.0% of the students of North Olmsted
High School. We later changed that
to only 150 students, because we found the correct number of students much less
than we thought, and we need to have less than 10.0% of the population.
We thought 1,602, however it was more around 1,530.
We decided 150 would be a good sample to send out.
We opened the list of all the students in
Then, we found a class they were in and sent them the survey, which is below:
SURVEY
AAJK
1.
How many adults (not brothers or sisters) live in your house?
(Check one)
_____ 1 Adult
_____ 2 Adults
_____ 3 or More Adults
2.
Please state your current cumulative Grade Point Average (GPA).
________________
3.
Are you Male or Female?
_____ Male
_____ Female
4.
What grade are you currently in?
_____ 9th Grade
_____ 10th Grade
_____ 11th Grade
_____ 12th Grade
5.
How old are you?
_____ 14 years old or younger _____ 15 years old
_____ 16 years old
_____ 17 years old
_____ 18 years old
_____ 19 years old or older
6.
If you currently reside in a one adult household, does the adult work
full time, part time, or are they unemployed?
_____ Full time job
_____ Part time job
_____ Unemployed
7.
If you currently reside in a two or more adult household, what is the
total number of jobs worked of each type by adults?
(ex.
2
Full Time – two jobs are full
time jobs)
_____ Full Time
_____ Part Time
_____ Unemployed
1 |
µ1 = The true mean grade point average from students from
single-parent households
µ2 = The true mean
grade point average from students from two or more parent households |
2 |
Ho: µ1 = µ2 |
3 |
Ha: µ1
µ2 |
4 |
α = 0.05 |
5 |
Assumptions: Sample is random, samples are independently selected.
We assume our sample is normal because of our fitted line plot
normality test. |
6 |
t =
=
0.08 |
7 |
p-value = 0.94 |
8 |
Conclusion: We
failed to reject our null hypothesis at any reasonable level of
significance because our P-value is much greater than Alpha (0.94).
Therefore, there is insufficient evidence to say that the true
mean grade point average from students from single-parent households
differs from the true mean grade point average from students from two or
more parent households. |
Test of Male GPA vs. Female GPA
1 |
µ1 = The true mean grade point average for Females
µ2 = The true mean
grade point average for Males |
2 |
Ho: µ1 = µ2 |
3 |
Ha: µ1
µ2 |
4 |
α = 0.05 |
5 |
Assumptions: Sample is random, samples are independently selected, both
sample sizes are large so we can assume normality with the Central
Limits Theorem. |
6 |
t =
=
2.36 |
7 |
p-value = 0.02 |
8 |
Conclusion: We
rejected the null hypothesis at the 0.05 level of significance because
our p-value was less than Alpha. Therefore, we have sufficient
evidence to say that there is a difference in the true mean grade point
average between males and females. |