Study

 

μ1=The average number of people who pack their lunch

μ2=The average number of people who bought their lunch

H0: μd=0

H: μd>0

α= .05

t=d/√s²/n

There is less than 30 samples of data but the dat looks normally distributed in a box plot and was random slection

t=-.75

p-value= .767

Since there is a p-value of .767 and that is much greater than α at any reasonable significance level I fail to reject H0. Therefore I fail to conclude that there is a difference  between the amount of kids who pack or buy lunch at North Olmsted High School at any reasonable significance level.
Paired T-Test and CI: pack, buy 

Paired T for pack - buy

             N   Mean  StDev  SE Mean
pack        12  82.00   9.87     2.85
buy         12  85.42   9.16     2.64
Difference  12  -3.42  15.70     4.53

95% lower bound for mean difference: -11.56
T-Test of mean difference = 0 (vs > 0): T-Value = -0.75  P-Value = 0.767

Graphs Data