Lunch Preference vs. Gender

The Study

Sampling

 For my study, the population of interest would be the entire student body of North Olmsted High School. The students chosen could be from any grade level or of any gender. My samples were obtained by assigning the entire student body a number. Then, by using a random number generator, I obtained, a sample of 150 students for my sample size.

            I decided to have a sample size of 150 students to reduce the amount of response bias being that some students might not return the surveys, they misplaced, or some of students go to Polaris.

Survey:

Please check which option applies to you.

 

Do you have a lunch period this year? Yes____  No_____

 

What is your gender? Male____ Female ____

 

On average which do you do most often? (Check one only please)

 

Pack a lunch from home ____  Buy a school lunch _____  Don’t eat a lunch _____

 

Tally for Discrete Variables: Lunch, Lunch2

 

Lunch Count Percent Lunch2 Count Percent

1 26 52.00 1 27 52.94

2 24 48.00 2 24 47.06

N= 50 N= 51

 

Test and CI for Two Proportions

Sample X N Sample p

1 24 78 0.307692

2 24 72 0.333333

Estimate for p(1) - p(2): -0.0256410

 

95% CI for p(1) - p(2): (-0.175131,

0.123849)

Test for p(1) - p(2) = 0 (vs not = 0): Z =

 -0.34 P-Value = 0.737

 

Significance Test

Ho:π12=0 The proportion of females over the proportion of males pack more lunches.

Ha:π12>0 The proportion of females over the proportion of males don't pack more lunches.

Significance level:α= 0.05

eq1015.jpg (5202 bytes)

Assumptions: The samples are independently chosen random samples.

Both sample sizes are large.

Calculation:

z= -0.034

p=0.737

Conclusion: We can fail to reject the null hypothesis at the 0.05 level of significance because the p-value is greater than alpha 0.05. Therefore we have insufficient evidence to say the proportion of females who pack a lunch is greater than the proportion of males who pack a lunch. 

     Data       

     Graphs